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+0.5x^2+17x-200=0
a = 0.5; b = 17; c = -200;
Δ = b2-4ac
Δ = 172-4·0.5·(-200)
Δ = 689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{689}}{2*0.5}=\frac{-17-\sqrt{689}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{689}}{2*0.5}=\frac{-17+\sqrt{689}}{1} $
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